/* 
 * Chatper 4 
 * Self Test
 * By: John Stile
 */
1. Rewrite the expression aa*bb+cc to ensure that addition is done first.

Answer:  aa*(bb+cc)  

2. What is printed as the value of xx in the following program?
#include <stdio.h> // 
int main(void)
{
  int xx,yy;
  yy=2;
  xx=yy*yy*yy;
  printf("The value of xx is %d\n", xx);
  
  return 0;
} 


Answer: Prints  "The value of xx is 8" and carrage return.

3. What is the output for the following code fragment?

int xx,yy;
xx=10;
yy=3;
if (xx==yy)
  printf("xx is equal to yy. Right?\n");
else
  printf("xx is not equal to yy\n");

Answer: 
  prints "xx is not equal to yy" and carrage return.

4. What is the output for the following code fragments?
a)
  int xx,yy;
  xx=10;
  yy=xx/4;
  printf("The value fo yy is %d\n", yy);

Answer:
  Prints "The value of yy is 2" and carrage return.

b) 
  int xx,yy;
  xx=10;
  yy=15;
  printf( "The value of yy is %f\n", yy=(float)xx/4);

Answer:
  Print "The value of yy is -0.854771

5. What is wrong with the following?

  int aa,bb;
  float average;
  average=aa+bb/2.0; // division of an int by a float
  printf("The average of aa and bb is %f\n", average);

Answer:
  initialize aa and bb
  paranthesis around aa+bb to allow addition before division

6. What is the output by each of the follwoing printf statements? Explain.
a) printf("%d \n", 'A' +38); // ascii value of A +38, printed as decimal
b) printf("%c \n", 'A' +38); // ascii value of A +38, printed as character
c) printf("%d \n", 'Z' -3);  // ascii value of Z -3, printed as decimal
d) printf("%c \n", 'Z' -3);  // ascii value of Z -3, printed as character
e) printf("%c \n", 'A' -10); // ascii value of A -10, printed as character
f) printf("%c \n", 'Z'+3);   // ascii value of Z +3, printed as character

7. What is wrong with the following code?  Fix it and make it work;

#include <stdio.h>
#include <math.h>

int main(void)
{
  int xx;
  xx=3;
  printf("The value of yy is %f\n", pow(2,xx) );

  return 0;
}